If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/4(x+2)^2-2=3
We move all terms to the left:
1/4(x+2)^2-2-(3)=0
Domain of the equation: 4(x+2)^2!=0We add all the numbers together, and all the variables
x∈R
1/4(x+2)^2-5=0
We multiply all the terms by the denominator
-5*4(x+2)^2+1=0
Wy multiply elements
-20x(x+1=0
| 1/4w=-21/2 | | 2w/3=4/9 | | 6.5w=-65. | | 2p-7=6p-23 | | 5(2z+10)+2=66 | | 119+18m=263 | | 5(v+1)=25 | | 2p-7=6-23 | | 3/4m=-131/2 | | 10p-2=3p+19 | | 46-2r+3=53 | | 14.09+m=32.09 | | 17-9f=-7(5f-4) | | K(x)=4x-2 | | 2(4x+3)=-5(5x-5)+3x | | 9/12-8/12x=1/2 | | 26n-17=425 | | 8p-9=9p-13 | | 4.5m=-81. | | 50-4n=190 | | 3(g-6)=-39 | | 18r-6=5r+49 | | 2(4x+2)=-5(3x-1)+3x | | 12v+8=138-v | | 3(4x+3)=-5(5x-4) | | w+19=23 | | 10x^2+3x=12-7x | | H(n)=2n-3 | | 5x=3x+6=-10 | | 2(3x+2)=-5(4x-5) | | 4(5x+1)=-5(5x-3) | | 8-25s-2.375=10 |